Discriminating method to study the resistance of spring particles approved

According to the above analysis, we first look at a college entrance examination simulation test, month 3x. month 43x, l block is statically released at the rightmost corpse point, because the left spring tension F is greater than the right friction force f, the block will accelerate to the left In the process of motion and friction, the frictional resistance f does not change. Compared with the vibration of the vertical spring, it is easy to prove that the block is a simple harmonic vibration.

According to the above analysis, we first look at a college entrance examination simulation test, month 3x. month 43x, l block is statically released at the rightmost corpse point, because the left spring tension F is greater than the right friction force f, the block will accelerate to the left During the movement and movement, the frictional resistance f is constant. Compared with the vertical spring vibration, it is easy to prove that the block is a simple harmonic vibration. The equilibrium position is not the O point but the right point.

Note: The calculation of the amplitude is taken as O, which is the starting point, and the periodic moving time is only half a cycle. 2 are at the right of point O and o, closer to o is closer to the right and closer to C. Both are at the right of the mouth and O, and the mouth: for the same position D. coincides with the point O. The answer is c. Pull the block to p: the point is released by static, and both do harmonic vibration, and the equilibrium position, that is, the maximum position of the block velocity, is at the right and the point distance is x, due to the resistance of the spring oscillator The calculation of the time, distance, etc. of the vibration exceeds the requirements of the college entrance examination knowledge, but it is in line with the knowledge of the competition, so the questions related to this appear in the competition test questions.

From the previous analysis, we can get the following conclusion: the nth vibration amplitude of the block A.=A(2n-1), showing the arithmetic progression. (Note: the amplitude is calculated by taking the balance position 01 and the port: as the starting point); the distance between the nth vibration end position and the O point, that is, the spring elongation (or shortening amount) is A.

It is also the arithmetic progression; what is the friction factor between the Sichuan block and the tabletop? (2) Find the maximum distance between the block stop point and the O point, and answer whether this is the block that can be reached during the movement. Maximum distance. (It is considered that the dynamic friction factor is equal to the static friction factor) vibrates n times, and the vibration time is the vibration path method.

If you only vibrate once, vibrate to the left, the amplitude is A: the two blocks will eventually be stationary, and the rest position cannot be outside the region o, o: because in the region. The spring force of the outer spring is greater than the friction force, and the external force is not zero. The position of the rest can only be within the area o; o: or, if the block is zero in the area O: O:, the object will be stationary.

Then: (1) If the nth vibration end position is. Point distance A. The nth vibration end position of the block is in the area. In addition to o:, the n+1th vibration will continue to be reversed; (2) If the nth vibration end position is at an distance from the O point An-xx, that is, A.>2x, the block number. The secondary vibration end position is in the area. :O: Within, and parked in the area. o: Within (An=2, the corresponding stop in the balance position 01 or 02).

At this time, the distance between the stop position and the mouth point, that is, the elongation (or the amount of shortening) of the spring is An-x. (x. In order to ensure that the object reciprocates multiple times, A is the maximum compression of the spring. When the block moves from the mouth to the right, the block reaches the point as far as possible because the object is reciprocated many times. Because the position of the corpus is the maximum extension position of the spring, if the spring reaches the right side of the corpse, the spring will undergo irreversible deformation.

Formaldehyde

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